36 lines
1.1 KiB
Plaintext
36 lines
1.1 KiB
Plaintext
BEGIN
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LONG INT days per year = 365,
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days per leap year = 366,
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secs per day = 24 * 3600,
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secs per hour = 3600,
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secs per min = 60;
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[1:12] LONG INT days in month := (31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31);
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PROC to epoch secs = ([] INT t) LONG REAL:
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BEGIN
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LONG INT year = t[1], month = t[2], day = t[3],
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hour = t[4], min = t[5], sek = t[6];
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LONG INT years = year - 1970;
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LONG INT leap years = years OVER 4 - years OVER 100 + years OVER 400;
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LONG INT days = years * days per year + leap years;
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IF year MOD 4 = 0 AND (year MOD 100 /= 0 OR year MOD 400 = 0)
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THEN days in month[2] := 29
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FI;
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FOR m FROM 1 TO month - 1 DO
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days +:= days in month[m]
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OD;
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days +:= day - 1;
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LONG REAL total = days * secs per day + hour * secs per hour + min * secs per min + sek;
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total
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END;
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[] INT lt = local time;
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print(("array: ", lt, newline));
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LONG REAL secs = to epoch secs(lt);
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print(("seconds: ", secs, newline))
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END |